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Proof step 10 from proof eq2 (previous step)

2 ^ i -1 * 2 = 2, 0 < i ⊦ i = 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
2 ^ i -1 = 1, 0 < i ⊦ i = 1

Rule argument

Additional information

Used simplifier rules: commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult% ⊦ 0 < i → (i * j = i ↔ j = 1); (s)