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Proof step 2 from proof eq2 (previous step)

2 ^ i = 2 ⊦ i = 1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ 0 < i → j ^ i = j ^ i -1 * j
Proof step 4:
2 ^ i = 2 ⊦ i = 1, 0 < i
Proof step 10:
2 ^ i -1 * 2 = 2, 0 < i ⊦ i = 1

Rule argument

spec: <toplevel> name: Pot-pos seq: ⊦ 0 < i → j ^ i = j ^ i -1 * j subst: [i, j] → [i, 2] flags: <all paths>

Additional information

Used terms: i, 2