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Proof step 5 from proof mod-2pot (previous step)

0 < i ⊦ (j * 2 ^ i) % 2 = 0, 0 ≤ j ∧ 0 < i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
0 < i, j < 0 ⊦ (j * 2 ^ i) % 2 = 0

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs% ⊦ i ≤ j ↔ ¬ j < i; (ss)