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Proof step 6 from proof mod-2pot (previous step)

0 < i, j < 0 ⊦ (j * 2 ^ i) % 2 = 0

User applied rule cut formula

And obtained the following new goals

Proof step 7:
j = ~ abs(j), j < 0, 0 < i ⊦ (j * 2 ^ i) % 2 = 0

Rule argument

fma: j = ~ abs(j)

Additional information

Used simplifier rules: ⊦ i < 0 → abs(i) = ~ i; (s)% ⊦ ~ ~ i = i; (s) Used formulas: j = ~ abs(j)