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Proof step 3 from proof pot-zero-01 (previous step)

0 < i ⊦ i ^ j = 0 ↔ j < 0 ∧ 1 < i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ i < 0 → j ^ i = 1 / j ^ abs(i)
Proof step 5:
0 < i ⊦ i ^ j = 0 ↔ j < 0 ∧ 1 < i, j < 0
Proof step 8:
0 < i, j < 0 ⊦ 1 / i ^ abs(j) = 0 ↔ j < 0 ∧ 1 < i

Rule argument

spec: <toplevel> name: Pot-neg seq: ⊦ i < 0 → j ^ i = 1 / j ^ abs(i) subst: [i, j] → [j, i] flags: <all paths>

Additional information

Used terms: j, i