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Proof step 8 from proof pot-zero-01 (previous step)

0 < i, j < 0 ⊦ 1 / i ^ abs(j) = 0 ↔ j < 0 ∧ 1 < i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
0 < i, j < 0 ⊦ 1 / i ^ ~ j = 0 ↔ 1 < i

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs% ⊦ i < 0 ∧ 0 ≤ j → i < j; (s)% ⊦ i < 0 → abs(i) = ~ i; (s)