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Proof step 2 from proof root-le (previous step)

i ≤ j, 0 ≤ i, 0 ≤ j ⊦ sqrt(i) ≤ sqrt(j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
sqrt(j) < sqrt(i), i ≤ j, 0 ≤ i, 0 ≤ j ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs% ⊦ i ≤ j ↔ ¬ j < i; (ss)