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Proof step 3 from proof root-le (previous step)

sqrt(j) < sqrt(i), i ≤ j, 0 ≤ i, 0 ≤ j ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ i ^2 ≤ j → ¬ sqrt(j) < i
Proof step 5:
sqrt(j) < sqrt(i), 0 ≤ j, 0 ≤ i, i ≤ j ⊦ sqrt(i) ^2 ≤ j

Rule argument

spec: <toplevel> name: square-nls seq: ⊦ i ^2 ≤ j → ¬ sqrt(j) < i subst: [i, j] → [sqrt(i), j] flags: <all paths>

Additional information

Used terms: sqrt(i), j