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Proof step 2 from proof blapp (previous step)

⊦ x.butlast = y ↔ x = y + x.last ', x = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
x = y + x.last ', x.last ∈ x ⊦ x.butlast = y, x = []

Rule argument

Additional information

Used simplifier rules: butlast-last: x ≠ [] ⊦ x.butlast + x.last ' = x;%in-15: ⊦ x + a ' = y → a ∈ y; (forward) from specification list%a: ⊦ (x + y) + z = x + y + z; from specification list