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Proof step 3 from proof blapp (previous step)

x = y + x.last ', x.last ∈ x ⊦ x.butlast = y, x = []

User applied rule insert elim lemma

And obtained the following new goals

Proof step 4:
x ≠ [] ⊦ a = x.last ∧ y = x.butlast ↔ x = y + a '

Rule argument

spec: <toplevel> name: last-elim seq: x ≠ [] ⊦ a = x.last ∧ y = x.butlast ↔ x = y + a ' subst: [x, a, y] → [x, a, y0] flags: <rotated> <all paths>

Additional information

Used simplifier rules: ⊦ x + y = z + y ↔ x = z; (s)%a: ⊦ (x + y) + z = x + y + z; from specification list Used terms: x, a, y0