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Proof step 24 from proof nu-is-UN (
previous step
)
monotone(compl(f)), monotone(f), compl(f)(S)(x0) → S(x0) ⊦ S(x), S(x0), f(λ x0. ¬ S(x0))(x0)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 25
:
monotone(f), monotone(compl(f)) ⊦ S(x0), S(x), compl(f)(S)(x0), f(λ x0. ¬ S(x0))(x0)
Rule argument
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