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Proof step 25 from proof nu-is-UN (
previous step
)
monotone(f), monotone(compl(f)) ⊦ S(x0), S(x), compl(f)(S)(x0), f(λ x0. ¬ S(x0))(x0)
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 26
:
⊦ compl(f)(S)(x) ↔ ¬ f(λ x0. ¬ S(x0))(x)
Rule argument
spec: <toplevel> name: compl-def seq: ⊦ compl(f)(S)(x) ↔ ¬ f(λ x0. ¬ S(x0))(x) subst: [x, S, f] → [x0, S, f] flags: <all paths>
Additional information
Used terms: x0, S, f