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Proof step 7 from proof l-03 (previous step)

m < m0, ∀ n0, m1, m2. n0 < n1 ∧ m1 < m2 → m2 = 0 ∨ m1 + n0 < m2 + n1, n = n1 ∨ n < n1 ⊦ m + n = n1 + m0, m0 = 0, n1 = 0, m + n < n1 + m0

Heuristic cut applied rule cut formula

And obtained the following new goals

Proof step 8:
m < m0, ∀ n0, m1, m2. n0 < n1 ∧ m1 < m2 → m2 = 0 ∨ m1 + n0 < m2 + n1, n = n1 ∨ n < n1 ⊦ m + n = n1 + m0, m0 = 0, n = n1, n1 = 0, m + n < n1 + m0

Rule argument

fma: n = n1

Additional information

Used simplifier rules: eq-01: ⊦ m + n = m + n0 ↔ n = n0;%a: ⊦ (m + n0) + n1 = m + n0 + n1;%c: ⊦ m + n = n + m;%l: ⊦ m + n < m + n0 ↔ n < n0; Used formulas: n = n1