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Proof step 8 from proof l-03 (previous step)

m < m0, ∀ n0, m1, m2. n0 < n1 ∧ m1 < m2 → m2 = 0 ∨ m1 + n0 < m2 + n1, n = n1 ∨ n < n1 ⊦ m + n = n1 + m0, m0 = 0, n = n1, n1 = 0, m + n < n1 + m0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
m < m0, n < n1, ∀ n0, m1, m2. n0 < n1 ∧ m1 < m2 → m2 = 0 ∨ m1 + n0 < m2 + n1 ⊦ m + n = n1 + m0, m0 = 0, n = n1, n1 = 0, m + n < n1 + m0

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0;