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Proof step 9 from proof l-03 (previous step)

m < m0, n < n1, ∀ n0, m1, m2. n0 < n1 ∧ m1 < m2 → m2 = 0 ∨ m1 + n0 < m2 + n1 ⊦ m + n = n1 + m0, m0 = 0, n = n1, n1 = 0, m + n < n1 + m0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: n, m, m0

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; Used terms: n, m, m0