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Proof step 2 from proof trans-01 (previous step)

n < n0, n0 < n1 ⊦ n +1 < n1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
n0 < n1, n < n0, n < n1 ⊦ n0 = 0, n1 = 0, n +1 < n1

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0;%trans: ⊦ n < n0 ∧ n0 < n1 → n < n1;