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Proof step 3 from proof trans-01 (previous step)

n0 < n1, n < n0, n < n1 ⊦ n0 = 0, n1 = 0, n +1 < n1

Heuristic structural induction applied rule structural induction

And closed the goal!

Rule argument

term: n1

Additional information

Used simplifier rules: gen: ⊦ ;%disj: ⊦ 0 ≠ n +1;%less-2: ⊦ n0 < n +1 ↔ n0 = n ∨ n0 < n;%lrec: ⊦ m +1 < n +1 ↔ m < n;%f: ⊦ m < n → n ≠ 0;%trans: ⊦ n < n0 ∧ n0 < n1 → n < n1;