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Proof step 2 from proof ls-succ (previous step)

m / n < m / (n + 1) ⊦ n = 0

User applied rule insert lemma

And obtained the following new goals

Proof step 3:
n ≠ 0 ⊦ m / (n + 1) ≤ m / n
Proof step 4:
m / n < m / (n + 1), m / (n + 1) ≤ m / n ⊦ n = 0

Rule argument

spec: <toplevel> name: le-succ seq: n ≠ 0 ⊦ m / (n + 1) ≤ m / n subst: [n, m] → [n, m]

Additional information

Used terms: n, m