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Proof step 4 from proof ls-succ (previous step)

m / n < m / (n + 1), m / (n + 1) ≤ m / n ⊦ n = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ m ≤ n ↔ ¬ n < m

Rule argument

spec: nat name: le-def seq: ⊦ m ≤ n ↔ ¬ n < m subst: [n, m] → [m / n, m / (n + 1)] flags: <all paths>

Additional information

Used terms: m / n, m / (n + 1)