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Proof step 36 from proof enc-invert (previous step)

maxenc(m) * (maxenc(m) + 1) = 2 * n0, m - n0 ≤ maxenc(m) ⊦ (maxenc(m) * (1 + maxenc(m))) / 2 + (m - n0) = m

User applied rule insert equation

And obtained the following new goals

Proof step 37:
maxenc(m) * (maxenc(m) + 1) = 2 * n0, m - n0 ≤ maxenc(m) ⊦ (2 * n0) / 2 + (m - n0) = m

Rule argument

pos: left 1 flags:

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic