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Proof step 37 from proof enc-invert (previous step)

maxenc(m) * (maxenc(m) + 1) = 2 * n0, m - n0 ≤ maxenc(m) ⊦ (2 * n0) / 2 + (m - n0) = m

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 38:
⊦ (2 * m) / 2 = m
Proof step 39:
maxenc(m) * (maxenc(m) + 1) = 2 * n0, m - n0 ≤ maxenc(m) ⊦ n0 + (m - n0) = m

Rule argument

spec: nat-div name: two-mdiv2-02 seq: ⊦ (2 * m) / 2 = m subst: [m] → [n0] flags: <all paths>

Additional information

Used terms: n0