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Proof step 39 from proof enc-invert (previous step)

maxenc(m) * (maxenc(m) + 1) = 2 * n0, m - n0 ≤ maxenc(m) ⊦ n0 + (m - n0) = m

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 40:
n ≤ m ⊦ (m - n) + n = m
Proof step 41:
maxenc(m) * (maxenc(m) + 1) = 2 * n0, m - n0 ≤ maxenc(m) ⊦ n0 + (m - n0) = m, n0 ≤ m

Rule argument

spec: nat name: prop-01 seq: n ≤ m ⊦ (m - n) + n = m subst: [n, m] → [n0, m] flags: <all paths>

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic Used terms: n0, m