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Proof step 7 from proof lzer (previous step)

log2(m + 1) = 0, m + 1 < 2^(m0 + 1), 2^ m0 < 2^(m0 + 1), 2^ m0 ≤ m + 1, 2^ m0 ≤ m + 1 ∧ m + 1 < 2^ m0 +1 → log2(m + 1) = m0 ⊦ m = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
log2(m + 1) = 0, m + 1 < 2^ 1, 2^ 0 < 2^ 1, 2^ 0 ≤ m + 1 ⊦ m = 0

Rule argument

Additional information

Used simplifier rules: ⊦ m +1 = m + 1; (s)