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Proof step 8 from proof lzer (previous step)

log2(m + 1) = 0, m + 1 < 2^ 1, 2^ 0 < 2^ 1, 2^ 0 ≤ m + 1 ⊦ m = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ m ≤ n ↔ ¬ n < m

Rule argument

spec: nat name: le-def seq: ⊦ m ≤ n ↔ ¬ n < m subst: [n, m] → [m + 1, 2^ 0] flags: <all paths>

Additional information

Used simplifier rules: one-01: ⊦ 2^ 1 = 2;%n < n0 ⊦ m + (* n) < (* n0) ↔ m < n0 - n; (s)% ⊦ m < 1 ↔ m = 0; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic Used terms: m + 1, 2^ 0