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Proof step 3 from proof gcd-eq (previous step)

gcd(m, n) = m, n < m ⊦ n = 0

User applied rule insert lemma

And obtained the following new goals

Proof step 4:
⊦ m ≠ 0 → gcd(m, n) ≤ m
Proof step 5:
gcd(m, n) = m, n < m, n ≠ 0 → gcd(n, m) ≤ n ⊦ n = 0

Rule argument

spec: <toplevel> name: gcd-le seq: ⊦ m ≠ 0 → gcd(m, n) ≤ m subst: [m, n] → [n, m]

Additional information

Used terms: n, m