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Proof step 5 from proof gcd-eq (previous step)

gcd(m, n) = m, n < m, n ≠ 0 → gcd(n, m) ≤ n ⊦ n = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: gcd-c seq: ⊦ gcd(m, n) = gcd(n, m) subst: [n, m] → [n, m] flags: <all paths>

Additional information

Used simplifier rules: fle-01: ⊦ m ≤ n ∧ n < n0 → m < n0; (forward) from specification nat%lf-01: ⊦ m < n ∧ n = n0 → m < n0; (forward) from specification nat-basic%fle: ⊦ m < n ∧ n ≤ n0 → m < n0; (forward) from specification nat% ⊦ m < n → n ≠ 0; (s)% ⊦ ¬ n < n; (s) Used terms: n, m