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Proof step 2 from proof add-le-right2-ls (previous step)

n0 < n1, m ≤ m0 + n0 ⊦ m < m0 + n1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
n0 < n1, m0 + n1 ≤ m, m ≤ m0 + n0 ⊦

Rule argument

Additional information

Used simplifier rules: lels: ⊦ m < n ↔ ¬ n ≤ m;% ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic