[Imprint][Data Privacy Statement][E-Mail]

Back to main index. View the specification. View theorem base summary, View theorem base listing, the used properties by spec, the dependency list, the symbol table,

Theorem base for Specification nat

This is a listing of all goals defined over the current specification. Axioms are marked yellow, proved theorems green and unproved theorems blue. Click on individual names to get more information on the proof.

Name: Sequent: Type:
sub-base ⊦ m - 0 = m An Axiom
sub-rec ⊦ m - n +1 = (m - n)-1 An Axiom
le-def ⊦ m ≤ n ↔ ¬ n < m An Axiom
gr-def ⊦ m > n ↔ n < m An Axiom
ge-def ⊦ m ≥ n ↔ ¬ m < n An Axiom
add ⊦ n ≤ m → ((m - n) + n0 = m ↔ n = n0) A User Theorem
add-01 ⊦ n ≤ m → m + n0 - n = (m - n) + n0 A User Theorem
add-02 ⊦ 1 + m + m ≤ n + n ↔ m < n A User Theorem
add-03 ⊦ n ≤ n0 → m + n0 - n = m + (n0 - n) A User Theorem
add-le-right2-lsm ≤ m0 + n0, n0 < n1 ⊦ m < m0 + n1 A User Theorem
add-ls-right2-lem < m0 + n0, n0 ≤ n1 ⊦ m < m0 + n1 A User Theorem
add-num-01n < n0 ⊦ m + (* n) = m0 + (* n0) ↔ m = m0 + (n0 - n) A User Theorem
add-num-02n0 < n ⊦ m + (* n) = m0 + (* n0) ↔ m + (n - n0) = m0 A User Theorem
add-num-03n < n0 ⊦ (* n) ≠ m0 + (* n0) A User Theorem
add-num-04n0 < n ⊦ (* n) = m0 + (* n0) ↔ n - n0 = m0 A User Theorem
add-sub-less ⊦ m ≤ n ∧ n0 ≤ m → (n - m) + n0 = n - (m - n0) A User Theorem
anti ⊦ m ≤ n → (n ≤ m ↔ m = n) A User Theorem
cancel-01 ⊦ m + n - n + n1 = m - n1 A User Theorem
elim-pred-cn ≠ 0 ⊦ m = n - 1 ↔ n = m + 1 A User Theorem
elim-subn ≤ m ⊦ n0 = m - n ↔ m = n0 + n A User Theorem
eq ⊦ m = n + 1 → ¬ m ≤ n A User Theorem
eq-01 ⊦ m + n - m = n A User Theorem
eq-02n ≤ m ⊦ (m - n) + n0 = n1 ↔ m + n0 = n + n1 A User Theorem
eq-03 ⊦ m + 1 = n → n - m = 1 A User Theorem
eq-add2n-1-eq-le ⊦ n = n0 + n1 + 1 ∧ n0 + n1 = m0 + m1 → (n < m0 ↔ false) A User Theorem
eq-pred ⊦ m = m0 ∧ m0 = n + 1 → m - n - 1 = 0 A User Theorem
eq-pred-01 ⊦ m = n + 1 → m - n - 1 = 0 A User Theorem
eqle-one ⊦ m = n + 1 ∧ n < n0 → m ≤ n0 A User Theorem
fle ⊦ m < n ∧ n ≤ n0 → m < n0 A User Theorem
fle-01 ⊦ m ≤ n ∧ n < n0 → m < n0 A User Theorem
ge ⊦ n ≥ m ↔ m ≤ n A User Theorem
l-num-01n < n0 ⊦ m + (* n) < m0 + (* n0) ↔ m < m0 + (n0 - n) A User Theorem
l-num-02n0 < n ⊦ m + (* n) < m0 + (* n0) ↔ m + (n - n0) < m0 A User Theorem
l-num-03n < n0 ⊦ (* n) < m0 + (* n0) A User Theorem
l-num-04n0 < n ⊦ (* n) < m0 + (* n0) ↔ n - n0 < m0 A User Theorem
l-num-05n < n0 ⊦ m + (* n) < (* n0) ↔ m < n0 - n A User Theorem
l-num-06n0 < n ⊦ ¬ m + (* n) < (* n0) A User Theorem
len ≤ m ⊦ (m - n) + m0 ≤ n0 ↔ m + m0 ≤ n0 + n A User Theorem
le-add ⊦ m + m0 ≤ m ↔ m0 = 0 A User Theorem
le-add-01 ⊦ n < m ∧ n0 < m0 → (m + m0 ≤ n + n0 ↔ false) A User Theorem
le-add-02 ⊦ n < m ∧ n0 < m0 → (m + m0 ≤ n + n0 + 1 ↔ false) A User Theorem
le-addex ⊦ m ≤ n ↔ (∃ n0. m + n0 = n) A User Theorem
le-ls-simp ⊦ m ≤ n → (n < m ↔ false) A User Theorem
le-num-01n < n0 ⊦ m + (* n) ≤ m0 + (* n0) ↔ m ≤ m0 + (n0 - n) A User Theorem
le-num-02n0 < n ⊦ m + (* n) ≤ m0 + (* n0) ↔ m + (n - n0) ≤ m0 A User Theorem
le-num-03n < n0 ⊦ (* n) ≤ m0 + (* n0) A User Theorem
le-num-04n0 < n ⊦ (* n) ≤ m0 + (* n0) ↔ n - n0 ≤ m0 A User Theorem
le-num-05n < n0 ⊦ m + (* n) ≤ (* n0) ↔ m ≤ n0 - n A User Theorem
le-num-06n0 < n ⊦ ¬ m + (* n) ≤ (* n0) A User Theorem
le-one ⊦ m ≤ n + 1 ∧ n < n0 → m ≤ n0 A User Theorem
le-rec ⊦ n ≠ 0 → (m ≤ n ↔ m = n ∨ m < n) A User Theorem
le-sum ⊦ n ≤ n0 ∧ n1 ≤ m → n + n1 ≤ n0 + m A User Theorem
lels ⊦ m < n ↔ ¬ n ≤ m A User Theorem
lels-02 ⊦ m ≠ n → (m ≤ n ↔ m < n) A User Theorem
lels-03 ⊦ m < n → m ≤ n A User Theorem
lels-04 ⊦ n + m ≤ m0 → ¬ n0 + m0 < m A User Theorem
lep ⊦ m ≤ m + n A User Theorem
lep-01 ⊦ m + n ≤ m ↔ n = 0 A User Theorem
lep-02 ⊦ m + n ≤ m + n0 ↔ n ≤ n0 A User Theorem
lepr ⊦ m ≠ 0 → ¬ m ≤ m - 1 A User Theorem
leprf ⊦ m ≤ m - 1 → m = 0 A User Theorem
ler ⊦ m ≤ m A User Theorem
les ⊦ m < n → (n ≤ m + 1 ↔ n = m + 1) A User Theorem
lessn ≤ m, n1 < n ⊦ (m - n) + n0 + n1 < m + n0 A User Theorem
less-01n ≤ m, n1 ≤ n ⊦ (m - n) + n0 + n1 ≤ m + n0 A User Theorem
less-02n ≤ m, n0 < n ⊦ (m - n) + n0 < m A User Theorem
less-03 ⊦ m - n0 < m - n1 ∧ n0 ≤ m ∧ n1 ≤ m → n1 < n0 A User Theorem
let ⊦ n ≤ n0 ∧ n0 ≤ n1 → n ≤ n1 A User Theorem
lez ⊦ 0 ≤ m A User Theorem
lez-01 ⊦ m ≤ 0 ↔ m = 0 A User Theorem
lsn0 ≤ n ⊦ m < n - n0 ↔ m + n0 < n A User Theorem
ls-01n0 ≤ n ⊦ n - n0 < m ↔ n < m + n0 A User Theorem
ls-02n0 ≤ n ⊦ m ≤ n - n0 ↔ m + n0 ≤ n A User Theorem
ls-03n0 ≤ n ⊦ n - n0 ≤ m ↔ n ≤ m + n0 A User Theorem
ls-04 ⊦ n ≤ m ∧ n0 ≤ m → (m - n < m - n0 ↔ n0 < n) A User Theorem
ls-05 ⊦ n < m → 0 < m - n A User Theorem
ls-06 ⊦ n ≤ m → (m - n < m ↔ n ≠ 0) A User Theorem
ls-07n ≤ m, n0 ≤ m ⊦ m - n < m - n0 ↔ n0 < n A User Theorem
ls-add-not ⊦ m ≤ m0 ∧ n ≤ n0 → ¬ m0 + n0 + n1 < m + n A User Theorem
ls-add-not-01 ⊦ m ≤ m0 ∧ n ≤ n0 → ¬ m0 + n0 < m + n A User Theorem
ls-add-not-02 ⊦ m ≤ m0 ∧ n ≤ n0 ∧ m1 ≤ n1 → ¬ m0 + n0 + n1 + n2 < m + n + m1 A User Theorem
ls-add-not-03 ⊦ m ≤ m0 ∧ n ≤ n0 ∧ m1 ≤ n1 → ¬ m0 + n0 + n1 < m + n + m1 A User Theorem
ls-le-simp ⊦ m < n → (n ≤ m ↔ false) A User Theorem
ls-pred ⊦ n + 1 < m → m - n - 1 < m A User Theorem
neq-01 ⊦ m0 ≤ m ∧ n + m ≤ n0 → n0 + 1 ≠ n + m0 A User Theorem
neq-add1 ⊦ n0 = n1 + n2 → (n2 = n0 + 1 ↔ false) A User Theorem
not-zero0 < n ⊦ (* n) ≤ m → m ≠ 0 A User Theorem
num-01 ⊦ n + 1 - 1 = n A User Theorem
num-02n ≠ 0 ⊦ (n - 1) + 1 = n A User Theorem
one-01 ⊦ m ≠ 0 → (m + n ≤ 1 ↔ m = 1 ∧ n = 0) A User Theorem
one-02 ⊦ m ≠ 0 → (m ≤ 1 ↔ m = 1) A User Theorem
plsm ≤ m0, n < n0 ⊦ m + n < m0 + n0 A User Theorem
pred ⊦ n < m → m - 1 - n = m - n - 1 A User Theorem
pred-01 ⊦ n < m → (m - n - 1) + 1 = m - n A User Theorem
pred-02m ≠ 0, n ≠ 0, n ≤ m ⊦ m - 1 - (n - 1) = m - n A User Theorem
pred-03 ⊦ n -1 = n - 1 A User Theorem
propn < m ⊦ m - 1 - n = m - n + 1 A User Theorem
prop-01n ≤ m ⊦ (m - n) + n = m A User Theorem
prop-02n ≤ m ⊦ (m - n) + 1 = m + 1 - n A User Theorem
prop-04 ⊦ m < m - n → m < n A User Theorem
prop-05m ≤ n ⊦ (n - m) + n0 = n + n0 - m A User Theorem
prop-06m ≠ 0, m ≤ n + 1 ⊦ n + 1 - m = n - (m - 1) A User Theorem
prop-07 ⊦ n < m → (m - n) + n = m A User Theorem
rax ⊦ m - n + 1 = m - n - 1 A User Theorem
recn ≤ m ⊦ m + 1 - n = (m - n) + 1 A User Theorem
shift ⊦ m - n - n0 = m - n0 - n A User Theorem
shift-01 ⊦ m - n - n0 = m - n + n0 A User Theorem
sub-add ⊦ n ≤ n0 → (m + (n0 - n)) + n = m + n0 A User Theorem
sub-add-01 ⊦ n0 ≤ n ∧ n ≤ m + n0 → m - (n - n0) = m + n0 - n A User Theorem
sub-le-rewm0 ≤ m, n0 ≤ n ⊦ m - m0 ≤ n - n0 ↔ m + n0 ≤ n + m0 A User Theorem
sub-ls ⊦ ¬ n + (m - n) < m A User Theorem
sub-ls-rewm0 < m, n0 < n ⊦ m - m0 < n - n0 ↔ m + n0 < n + m0 A User Theorem
sub-same ⊦ n ≤ m → m - (m - n) = n A User Theorem
sub-succ ⊦ m0 ≤ n ∧ n ≤ m → m - (n - m0) = (m - n) + m0 A User Theorem
succ ⊦ n + 1 - n = 1 A User Theorem
succ-01 ⊦ m + 1 ≤ n ↔ m < n A User Theorem
succ-02 ⊦ m < n + 1 ↔ m ≤ n A User Theorem
succ-04n ≤ m ⊦ m + 1 - n - 1 = m - n A User Theorem
succ-05 ⊦ n + 1 < m → m - n - 1 ≠ 0 A User Theorem
trans-le-lem ≤ n, n ≤ n0 ⊦ m ≤ n0 A User Theorem
trans-le-lsm ≤ n, n < n0 ⊦ m < n0 A User Theorem
trans-ls-lem < n, n ≤ n0 ⊦ m < n0 A User Theorem
zero ⊦ m - m = 0 A User Theorem
zero-01 ⊦ n < m → m - n ≠ 0 A User Theorem
zero-02 ⊦ m ≤ n → (n - m = 0 ↔ n = m) A User Theorem