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Proof step 12 from proof anti (
previous step
)
n0 + 1 < m, n0 < m, m ≤ n0 + 1 ⊦ m = n0 + 1
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 13
:
⊦ m ≤ n ↔ ¬ n < m
Rule argument
spec: <toplevel> name: le-def seq: ⊦ m ≤ n ↔ ¬ n < m subst: [n, m] → [n0 + 1, m] flags: <all paths>
Additional information
Used terms: n0 + 1, m