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Proof step 2 from proof l-num-04 (previous step)

n0 < n ⊦ n < m0 + n0 ↔ n - n0 < m0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: le-def: ⊦ m ≤ n ↔ ¬ n < m;%ls-01: n0 ≤ n ⊦ n - n0 < m ↔ n < m + n0;% ⊦ m < n → ¬ n < m; (s)