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Proof step 2 from proof le-add-01 (previous step)

n < m, n0 < m0 ⊦ m + m0 ≤ n + n0 ↔ false

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
n < m, n0 < m0, m + m0 ≤ n + n0 ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic