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Proof step 8 from proof le-sum (previous step)

m0 + n0 + 1 < n + n1, n1 ≤ m0 + 1, n ≤ n0, ∀ n, n0, n1. n ≤ n0 ∧ n1 ≤ m0 → n + n1 ≤ n0 + m0 ⊦

User applied rule all left

And obtained the following new goals

Proof step 9:
m0 + n0 + 1 < n + n1, n ≤ n0, n1 ≤ m0 + 1, n ≤ n0 ∧ n1 ≤ m0 → n + n1 ≤ n0 + m0, ∀ n, n0, n1. n ≤ n0 ∧ n1 ≤ m0 → n + n1 ≤ n0 + m0 ⊦

Rule argument

pos: left 4 terms: n, n0, n1 abort: F discard: F computed: F

Additional information

Used terms: n, n0, n1