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Proof step 2 from proof pls (previous step)

n < n0, m ≤ m0 ⊦ m + n < m0 + n0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
n < n0, m0 + n0 ≤ m + n, m ≤ m0 ⊦

Rule argument

Additional information

Used simplifier rules: lels: ⊦ m < n ↔ ¬ n ≤ m;% ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic