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Proof step 2 from proof pred (previous step)

n < m ⊦ m - 1 - n = m - n - 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
n < m ⊦ m - 1 - n = m - n - 1

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic