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Proof step 15 from proof sort-max-max-list (previous step)

max(sort(x0)) = max(x0), max(x0) < a, a < sort(x0).last, max(x0) < sort(x0).last ⊦ max(sort(x0) + a ') = a, x0 = [], ordered≤(sort(x0) + a ')

User applied rule insert equation

And obtained the following new goals

Proof step 16:
max(sort(x0)) = max(x0), max(sort(x0)) < sort(x0).last, a < sort(x0).last, max(sort(x0)) < a ⊦ max(sort(x0) + a ') = a, x0 = [], ordered≤(sort(x0) + a ')

Rule argument

pos: left 1 flags: rotate

Additional information