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Proof step 16 from proof sort-max-max-list (previous step)

max(sort(x0)) = max(x0), max(sort(x0)) < sort(x0).last, a < sort(x0).last, max(sort(x0)) < a ⊦ max(sort(x0) + a ') = a, x0 = [], ordered≤(sort(x0) + a ')

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: ordered-max seq: ⊦ x ≠ [] ∧ ordered≤(x) → max(x) = x.last subst: [x] → [sort(x0)] flags: <all paths>

Additional information

Used simplifier rules: ⊦ sort(x) = [] ↔ x = []; (s)% ⊦ ordered≤(sort(x)); (s)% ⊦ ¬ a < a; (s) Used terms: sort(x0)