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Proof step 4 from proof Diff-rec-rev (previous step)

∀ st, a. (st \ s0) -- a = (st -- a) \ s0 ⊦ (st \ s0) -- a0 -- a = ((st -- a) \ s0) -- a0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ st -- a -- b = st -- b -- a
Proof step 6:
∀ st, a. (st \ s0) -- a = (st -- a) \ s0 ⊦ (st \ s0) -- a -- a0 = ((st -- a) \ s0) -- a0

Rule argument

spec: store name: sw-01 seq: ⊦ st -- a -- b = st -- b -- a subst: [b, a, st] → [a, a0, st \ s0] flags: <all paths>

Additional information

Used terms: a, a0, st \ s0