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Proof step 6 from proof Diff-rec-rev (previous step)

∀ st, a. (st \ s0) -- a = (st -- a) \ s0 ⊦ (st \ s0) -- a -- a0 = ((st -- a) \ s0) -- a0

User applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: st, a abort: F discard: F computed: F

Additional information

Used terms: st, a