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Proof step 10 from proof elim-fromto (previous step)

# σ0 = ⌜n⌝ , σ0 = ⌜nf⌝ , ⌜x⌝ = σ0 + σ1, n ≤ # x ⊦ σ0 = ⌜x to n⌝ ∧ σ1 = ⌜x from n⌝

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: append-inf: ⊦ ⌜nf⌝ + σ = ⌜nf⌝ ;%append-assoc: ⊦ (σ + σ1) + σ2 = σ + σ1 + σ2;% ⊦ ⌜x⌝ ≠ ⌜nf⌝ ; (s)