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Proof step 5 from proof elim-fromto (previous step)

# σ0 = ⌜n⌝ , ⌜x⌝ = σ0 + σ1, n ≤ # x ⊦ σ0 = ⌜x to n⌝ ∧ σ1 = ⌜x from n⌝

User applied rule constructor cut

And obtained the following new goals

Proof step 6:
# σ0 = ⌜n⌝ , σ0 = ⌜x0⌝ , ⌜x⌝ = σ0 + σ1, n ≤ # x ⊦ σ0 = ⌜x to n⌝ ∧ σ1 = ⌜x from n⌝
Proof step 10:
# σ0 = ⌜n⌝ , σ0 = ⌜nf⌝ , ⌜x⌝ = σ0 + σ1, n ≤ # x ⊦ σ0 = ⌜x to n⌝ ∧ σ1 = ⌜x from n⌝

Rule argument

var: σ0

Additional information

Used simplifier rules: stream freely generated by ⌜ ⌝, ⌜ ⌝;;