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Proof step 5 from proof inv-inverts-leq (previous step)

⌜nσ[n]⌝ < leninv(nσ), ⌜n⌝ < # nσ, (leninv(nσ) = ∞ ⊃ ⌜λ m. max∞(λ n. ⌜n⌝ < # nσ ∧ nσ[n] = m).n⌝ ;⌜λ m. max∞(λ n. ⌜n⌝ < # nσ ∧ nσ[n] = m).n⌝ to leninv(nσ).n)[nσ[n]] < n, stutf(nσ) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
⌜n⌝ < # nσ, ⌜nσ[n]⌝ < leninv(nσ), (leninv(nσ) = ∞ ⊃ ⌜λ m. max∞(λ n. ⌜n⌝ < # nσ ∧ nσ[n] = m).n⌝ ;⌜(λ m. max∞(λ n. ⌜n⌝ < # nσ ∧ nσ[n] = m).n) to leninv(nσ).n⌝ ) [nσ[n] ] < n, stutf(nσ) ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ ⌜nnf⌝ to n = ⌜nnf to n⌝ ; (s)