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Proof step 6 from proof inv-inverts-leq (previous step)

⌜n⌝ < # nσ, ⌜nσ[n]⌝ < leninv(nσ), (leninv(nσ) = ∞ ⊃ ⌜λ m. max∞(λ n. ⌜n⌝ < # nσ ∧ nσ[n] = m).n⌝ ;⌜(λ m. max∞(λ n. ⌜n⌝ < # nσ ∧ nσ[n] = m).n) to leninv(nσ).n⌝ ) [nσ[n] ] < n, stutf(nσ) ⊦

User applied rule case distinction

And obtained the following new goals

Proof step 7:
leninv(nσ) = ∞, ⌜nσ[n]⌝ < leninv(nσ), ⌜n⌝ < # nσ, ⌜λ m. max∞(λ n. ⌜n⌝ < # nσ ∧ nσ[n] = m).n⌝ [nσ[n]] < n, stutf(nσ) ⊦
Proof step 31:
⌜nσ[n]⌝ < leninv(nσ), ⌜n⌝ < # nσ, ⌜(λ m. max∞(λ n. ⌜n⌝ < # nσ ∧ nσ[n] = m).n) to leninv(nσ).n⌝ [nσ[n]] < n, stutf(nσ) ⊦ leninv(nσ) = ∞

Rule argument

pos: left 3

Proof step 6 from proof inv-inverts-leq (previous step)

User applied rule case distinction

And obtained the following new goals

Rule argument

Additional information