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Proof step 10 from proof less-leninv (previous step)

# nσ = ∞, nσ[n + 1] = nσ[n] + 1, m = m0 +1, ⌜m⌝ = leninv(nσ), stutf(nσ), m ≤ nσ[n] ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
# nσ = ∞, ⌜m0⌝ + ⌜1⌝ = leninv(nσ), nσ[n + 1] = nσ[n] + 1, m0 < nσ[n], stutf(nσ) ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m + 1 ≤ n ↔ m < n; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ ⌜m + n⌝ = ⌜m⌝ + ⌜n⌝ ; (s)% ⊦ m +1 = m + 1; (s)