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Proof step 5 from proof less-leninv (previous step)

# nσ = ∞, nσ[n + 1] = nσ[n] + 1, ⌜m⌝ = leninv(nσ), stutf(nσ), m ≤ nσ[n] ⊦

User applied rule constructor cut

And obtained the following new goals

Proof step 6:
# nσ = ∞, nσ[n + 1] = nσ[n] + 1, m = 0, ⌜m⌝ = leninv(nσ), stutf(nσ), m ≤ nσ[n] ⊦
Proof step 10:
# nσ = ∞, nσ[n + 1] = nσ[n] + 1, m = m0 +1, ⌜m⌝ = leninv(nσ), stutf(nσ), m ≤ nσ[n] ⊦

Rule argument

var: m

Additional information

Used simplifier rules: nat freely generated by 0, +1;;