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Proof step 2 from proof monls-ls (previous step)

m < n, ⌜n⌝ < # nσ, mon<(nσ) ⊦ nσ[m] < nσ[n]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
m < n, ⌜n⌝ < # nσ, mon<(nσ), nσ[n] ≤ nσ[m] ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m < n ↔ ¬ n ≤ m; (ss)