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Proof step 3 from proof monls-ls (previous step)

m < n, ⌜n⌝ < # nσ, mon<(nσ), nσ[n] ≤ nσ[m] ⊦

User applied rule structural induction

And obtained the following new goals

Proof step 4:
m1 +1 = n - m, ⌜n⌝ < # nσ, m < n, mon<(nσ), nσ[n] ≤ nσ[m], ∀ n, m, nσ. ¬(m1 = n - m ∧ m < n ∧ ⌜n⌝ < # nσ ∧ mon<(nσ) ∧ nσ[n] ≤ nσ[m]) ⊦

Rule argument

term: n - m

Additional information

Used simplifier rules: nat freely generated by 0, +1;;% ⊦ n < m → m - n ≠ 0; (s)