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Proof step 40 from proof stutf-maxinf-is-fin (previous step)

# nσ = ∞, nσ[n2] = nσ[n0], stutf(nσ), ∀ n1. ¬ n1 < n2 → nσ[n1] = nσ[n0] ⊦ ∃ n1. n < n1 ∧ nσ[n1] = nσ[n0], n < n2 ∧ nσ[n2] = nσ[n0]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 41:
# nσ = ∞, nσ[n2] = nσ[n0], stutf(nσ), n2 ≤ n, ∀ n1. ¬ n1 < n2 → nσ[n1] = nσ[n0] ⊦ ∃ n1. n < n1 ∧ nσ[n1] = nσ[n0]

Rule argument

Additional information

Used simplifier rules: ⊦ m < n ↔ ¬ n ≤ m; (ss)