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Proof step 41 from proof stutf-maxinf-is-fin (previous step)

# nσ = ∞, nσ[n2] = nσ[n0], stutf(nσ), n2 ≤ n, ∀ n1. ¬ n1 < n2 → nσ[n1] = nσ[n0] ⊦ ∃ n1. n < n1 ∧ nσ[n1] = nσ[n0]

User applied rule exists right

And obtained the following new goals

Proof step 42:
# nσ = ∞, nσ[n2] = nσ[n0], stutf(nσ), n2 ≤ n, ∀ n1. ¬ n1 < n2 → nσ[n1] = nσ[n0] ⊦ ∃ n1. n < n1 ∧ nσ[n1] = nσ[n0], n < n + 1 ∧ nσ[n + 1] = nσ[n0]

Rule argument

pos: right 1 terms: n + 1 abort: F discard: F computed: T

Additional information

Used terms: n + 1