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Proof step 6 from proof not-always-decrease (previous step)

∀ a0. a0 ≪ a → \A ∀ A, a1. a0 ≠ A ∨ ¬ □ ⟨a1 := A⟩ (◇ A ≪ a1) ∨ a1 ≠ A ⊦ \A ∀ A, a0. a ≠ A ∨ ¬ □ ⟨a0 := A⟩ (◇ A ≪ a0) ∨ a0 ≠ A

User applied rule pall focus right

And obtained the following new goals

Proof step 7:
∀ a0. a0 ≪ a → \A ∀ A, a1. a0 ≠ A ∨ ¬ □ ⟨a1 := A⟩ (◇ A ≪ a1) ∨ a1 ≠ A ⊦ ∀ A, a0. a ≠ A ∨ ¬ □ ⟨a0 := A⟩ (◇ A ≪ a0) ∨ a0 ≠ A

Rule argument

pos: right 1

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