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Proof step 14 from proof wand-right (previous step)

∀ H. P(H) → ((Q0 -* Q1))(H), ∃ H0, H1. H0 ⊥ H1 ∧ H = H0 ∪ H1 ∧ P(H0) ∧ Q0(H1) ⊦ Q1(H)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information